2(x/x+x)^2-5(x/x+1)+2=0

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Solution for 2(x/x+x)^2-5(x/x+1)+2=0 equation: 



2(x/x+x)^2-5(x/x+1)+2=0



Domain of the equation: x+x)^2!=0

x∈R





Domain of the equation: x+1)!=0

x∈R



We add all the numbers together, and all the variables

2(+x+x/x)^2-5(x/x+1)+2=0

We multiply parentheses

2(+x+x/x)^2-5x-5+2=0

We multiply all the terms by the denominator


2(+x+x-5x*x)^2-5*x)^2+2*x)^2=0

We add all the numbers together, and all the variables

2(+2x-5x*x)^2-5*x)^2+2*x)^2=0

Wy multiply elements

-5x^2+2(+2x-5x*x)^2=0

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